X^2+5x+4=2x^2-10

Solution for X^2+5x+4=2x^2-10 equation:

X^2+5X+4=2X^2-10

We move all terms to the left:

X^2+5X+4-(2X^2-10)=0

We get rid of parentheses

X^2-2X^2+5X+10+4=0

We add all the numbers together, and all the variables

-1X^2+5X+14=0

a = -1; b = 5; c = +14;
Δ = b2-4ac
Δ = 52-4·(-1)·14
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-9}{2*-1}=\frac{-14}{-2}
=+7
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+9}{2*-1}=\frac{4}{-2}
=-2
$